All the blocks more with common acceleration a under the force
F = 60 N.
F = (m1 + m2 + m3 )a
a = \(\frac{F}{(m_1 + m_2 + m_3)}\)a = 1 m/s2
to determine, T1 →Free body diagram of m1.
T1 = m1 a = 10 x 1 = 10 N
to determine, T2 →Free body diagram of m3
F – T2 = m3 a
Solving, we get T2 = 30 N