Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
989 views
in Laws of Motion by (48.2k points)
closed by

Three blocks of masses ml = 10 kg, m2 = 20 kg are connected by strings on smooth horizontal surface and pulled by a force of 60 N. Find the acceleration of the system and frictions in the string.

1 Answer

+1 vote
by (48.6k points)
selected by
 
Best answer

All the blocks more with common acceleration a under the force 

F = 60 N. 

F = (m1 + m2 + m3 )a 

a = \(\frac{F}{(m_1 + m_2 + m_3)}\)a = 1 m/s2 

to determine, T1 →Free body diagram of m1.

T1 = m1 a = 10 x 1 = 10 N 

to determine, T2 →Free body diagram of m3

F – T2 = m3

Solving, we get T2 = 30 N

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...