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in Laws of Motion by (48.1k points)
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A hunter has a machine gun that can fire 50g bullets with a velocity of 150 ms A 60 kg tiger springs at him with a velocity of 10 ms-1. How many bullets must the hunter fire into the target so as to stop him in his track?

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Given m = mass of bullet = 50 gm = 0.50 kg 

M = mass of tiger = 60 kg 

v = Velocity of bullet – 150 m/s

V = Velocity of tiger = – 10 m/s 

(v It is coming from opposite direction n = no. of bullets fired per second at the tiger so as to stop it.)

Pi = 0, before firing ……..(i)

Pf = n (mv) + MV …………(ii) 

∴ From the law of conservation of momentum, 

Pi = Pf 

⇒ 0 = n (mv) + MV 

n = \(\frac{MV}{mv}\)\(\frac{-60 \times (-10)}{0.05 \times 150}\) = 80

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