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in Work, Energy and Power by (48.2k points)
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Calculate the work done by a force of 30N in lifting a load of 2 Kg to a height of 10m(g = 10 ms-1 )

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Given:

F = 30 N, load (m) = 2 kg; height = 10 m, g 

= 10 ms-2 

Gravitational force F = mg = 30 N 

The distance moved h = 10 m 

Work done on the object W = Fh = 30 × 10 = 300 J.

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