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Suppose that P and Q are points on the sides AB and AC respectively of triangle ABC. The perpendicular to the sides AB and AC at P and Q respectively meet at D, an interior point of triangle ABC. If M is the midpoint of BC, prove that PM=QM if and only if angle(BDP)=angle(CDQ).
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Where is point F in angle(BDF)?
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Sorry! it's angle(BDP) and not angle(BDF). I have changed it.

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