Question

Spring A and B are identical except that A is stiffer than B, i.e., force constant k_A > k_B . In which spring is more work expended if they are stretched by the same amount?

Answer 1

W = \(\frac{1}{2}\)Kx²

\(\frac{W_A}{W_B}\) = \(\frac{K_A}{K_B}\), for same x

As k_A>K_B so W_A > W_B.