Question

A truck of mass 1000 kg accelerates uniformly from rest to a velocity of 15 ms^-1 in 5 seconds. Calculate 

(i) its acceleration, 

(ii) its gain in K.E., 

(iii) average power of the engine during this period, neglect friction.

Answer 1

(i) \(a = \frac{v-u}{t}\) = 3m/s²

(ii) Gain in K.E. = \(\frac{1}{2}\)m(v²- u²) = 1.125 x 10⁵ J

(iii) P = \(\frac{W}{t}\) = 22500W.