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If A × A has 16 elements, S = {(a, b) ∈ A × A : a < b} ; (-1, 2) and (0, 1) are two elements of S, then find the remaining elements of S.

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n(A × A) = 16 ⇒ n( A) = 4 

S ={(-1, 0), (-1, 1), (0, 2), (1, 2)}

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