Sarthaks Test
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in Mathematics by (49.8k points)

In a game two players A and B take turns in throwing a pair of fair dice starting with player A and total of scores on the two dice, in each throw is noted. A wins the game if he throws a total of 6 before B throws a total of 7 and B wins the game if he throws a total of 7 before A throws a total of six The game stops as soon as either of the players wins. The probability of A winning the game is : 

(1) 31/61 

(2) 5/6 

(3) 5/31 

(4) 30/61

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2 Answers

+1 vote
by (47.6k points)

Answer is (4) 30/61

0 votes
ago by (15 points)
P(6)=5/36

P(7)=6/36=1/6

P(A wins)=1/6 + 31/36 * 5/6 * 1/6 ..........................

                 =1/6[1/(1-155/216)]

                  = 30/61

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