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If the point P on the curve, 4x^2 + 5y^2 = 20 is farthest from the point Q(0, –4), then PQ^2 is equal to :

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If the point P on the curve, 4x2 + 5y2 = 20 is farthest from the point Q(0, –4), then PQ2 is equal to : 

(1) 21 (2) 36 (3) 48 (4) 29

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1 Answer

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The correct option is (2) 36.

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