Question

Let α > 0, β > 0 be such that α³ + β² = 4. If the maximum value of the term independent of x in the binomial expansion of (αx^1/9 +βx^1/6)¹⁰ is 10k, then k is equal to :

(1) 176 

(2) 336 

(3) 352 

(4) 84

Answer 1

Answer is (2) 336

Let t_{r + 1} denotes

r + 1^th term of (αx^1/9 +βx^1/6)¹⁰ 

So, 10 k = ¹⁰C₄ 16

⇒ K = 336

Comments

Nice explanation