Let y = y(x) be the solution of the differential equation, \(\frac{2+sinx}{y+1}.\frac{dy}{dx}\) = - cos x,y >0) = 1. If y(π) = a and \(.\frac{dy}{dx}\) at x = π is b, the the ordered pair (a,b) is equal to :
(1) (2,1)
(2) (2,3/2)
(3) (1,-1)
(4) (1,1)
