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+1 vote
17.8k views
in Mathematics by (48.6k points)

If lim (x→1) \(\frac{x+x^2+x^3+ ...+x^n-n}{x-1}\) = 820,(n∈N) then the value of n is equal to ....

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1 Answer

+1 vote
by (43.8k points)

⇒1 + 2 + ..... + n = 820

⇒ n(n + 1) = 2 × 820

⇒n(n + 1) = 40 × 41

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