Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
3.1k views
in JEE by (40 points)

what volume (in ml)of 0.2M H2SO4 solution should be mixed with the 40ml of 0.1M NaOH SOLUTION such that the resulting solution has concentration of H2SO4  as (6/55)M

Please log in or register to answer this question.

1 Answer

–1 vote
by (20.4k points)

Solution: We know that resultant molarity is given by

Resultant Molarity = (M1V1+M2V2)/(V1+V2)

we have M1 = 0.1, V1 = 40ml = 0.04 litre

M2 = 0.2, V2 = ?

Now putting the values in above formula we get,

(0.1x0.04 + 0.2xV2)/0.04+V2 = 6/55

=> 0.004+0.2V2 = (0.24+6V2)/55

=> 0.22+11V2 = 0.24+6V2

=> 5V2 = 0.02

=> V2 = 0.004

Hence, V2 = 0.004 litre or 4ml

by (40 points)
edited by
your answer is
wrong, answer is 70 ml

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...