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+1 vote
1.8k views
in CBSE by (40 points)
what volume (in ml)of 0.2M H2SO4 solution should be mixed with the 40ml of 0.1M NaOH SOLUTIONsuchthat the resulting solution has concentration of H2SO4  as (6/55)M

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1 Answer

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by (20.4k points)

Solution: We know that resultant molarity is given by

Resultant Molarity = (M1V1+M2V2)/(V1+V2)

we have M1 = 0.1, V1 = 40ml = 0.04 litre

M2 = 0.2, V2 = ?

Now putting the values in above formula we get,

(0.1x0.04 + 0.2xV2)/0.04+V2 = 6/55

=> 0.004+0.2V2 = (0.24+6V2)/55

=> 0.22+11V2 = 0.24+6V2

=> 5V2 = 0.02

=> V2 = 0.004 litre

Hence, V2 = 0.004 litre or 4ml

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