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+1 vote
28.4k views
in Physics by (48.5k points)

When radiation of wavelength λ is used to illuminate a metallic surface, the stopping potential is V. When the same surface is illuminated with radiation of wavelength 3λ, the stopping potential is \(\frac{V}{4}\) . If the threshold wavelength for the metallic surface is n then value of n will be ..........

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1 Answer

+1 vote
by (43.7k points)

∴ λ0 = 9λ So, n = 9

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