# Find the oxidation state of sodium in Na2O2.

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Find the oxidation state of sodium in Na2O2

by (1.1k points)

Each oxygen in a peroxide is assigned a formal charge of -1. Since sodium peroxide is neutral overall, each sodium atom is assigned an oxidation number of +1.

by (41 points)

## Let x be the oxidation station of sodium in Na2​O2​.

therefore
Na2= 2x  &  O2= (-1)2
= 2x+(-2)=0
=2x-2=0
x=(-2)/2
x=(-1)