Question

The mole fraction of glucose (C₆ H₁₂ O₆ ) in an aqueous binary solution is 0.1. The mass percentage of water in it, to the nearest integer, is ______.

Answer 1

47

Let total mole is 1 mol then mole of glucose will be 0.1 and mole of water will be 0.9 

so mass % of water = (0.9 x 18)/(0.1 x 180 + 0.9 x 18) x 100

= 47.36 

= 47