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If n(A) = 2 and n(B ∪ C) = 3, then n[(A × B) ∪ (A × C)] is …..

(a) 23

(b) 32 

(c) 6 

(d) 5

1 Answer

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Best answer

(c) 6

n[(A × B) ∪ (A × C)] = n[ A × (B ∪ C)] 

= n(A) × n(B ∪ C) = 2 × 3 = 6

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