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+1 vote
48.5k views
in Physics by (48.1k points)

An electron is accelerated from rest through a potential difference of V volt. If the de Broglie wavelength of the electron is 1.227 × 10–2 nm, the potential difference is :

(1) 104

(2)10

(3) 102

(4) 103 V

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1 Answer

0 votes
by (48.5k points)

Correct answer is (1) 104 V

λ = 1.227 × 10–2 nm 

= 0.1227 Å

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