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+2 votes
39.1k views
in Physics by (48.2k points)

In a guitar, two strings A and B made of same material are slightly out of tune and produce beats of frequency 6 Hz. When tension in B is slightly decreased, the beat frequency increases to 7 Hz. If the frequency of A is 530 Hz, the original frequency of B will be:

(1) 537 Hz 

(2) 523 Hz 

(3) 524 Hz 

(4) 536 Hz

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1 Answer

+1 vote
by (48.6k points)

Correct answer is (3) 524 Hz

Guitar string i.e. string is fixed from both ends

Frequency ∝ (Tension) 

If tension in B slightly decrease then frequency of B decrease.

If B is 536 Hz, as the frequency decreases, beats with A also decreases. 

If B is 524 Hz, as the frequency decreases, beats with A increases.

∴ original frequency of B will be 524 HZ.

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