We have, P(A ⋃ B) = P(A ⋂ B)
By General Addition Rule,
P(A) + P (B) – P(A ⋂ B) = P(A ⋃ B)
⇒ P(A) + P (B) – P(A ⋂ B) = P(A ⋂ B) [given]
⇒ [P(A) – P(A ⋂ B)] + [P(B) – P(A ⋂ B)] = 0
But P(A) – P(A ⋂ B) ≥ 0
and P(B) – P(A ⋂ B) ≥ 0
[∵ P(A ⋂ B) ≤ P(A) or P(B)]
⇒ P(A) – P(A ⋂ B) = 0
and P(B) – P(A ⋂ B) = 0
⇒ P(A) = P(A ⋂ B) …(i)
and P(B) = P(A ⋂ B) …(ii)
From (i) and (ii), we get
∴ P(A) = P(B)
Hence, the correct option is (A).