Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.2k views
in Probability by (49.0k points)
closed by

Fill in the blanks:

If e1, e2, e3, e4 are the four elementary outcomes in a sample space and P(e1) =.1, P(e2) = .5, P (e3) = .1, then the probability of e4 is ______.

1 Answer

+2 votes
by (50.4k points)
selected by
 
Best answer

Given: P(e1) = 0.1, P(e2) = 0.5, P(e3) = 0.1

We know that,

Sum of all probabilities = 1

∴ P(e1) + P(e2) + P(e3) + P(e4) = 1

⇒ 0.1 + 0.5 + 0.1 + P(e4) = 1

⇒ P(e4) = 1 – 0.7

⇒ P(e4) = 0.3

Ans. If e1, e2, e3, e4 are the four elementary outcomes in a sample space and P(e1) =.1, P(e2) = .5, P (e3) = .1, then the probability of e4 is 0.3

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...