Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.5k views
in Sets, Relations and Functions by (50.4k points)
closed by

Let f :R → R be defined by

Then f (– 1) + f (2) + f (4) is

A. 9
B. 14
C. 5
D. none of these

1 Answer

+1 vote
by (49.0k points)
selected by
 
Best answer

Given that,

Now,

f(-1) = 3(-1) = -3 [since -1<1 and f(x) = 3x for x≤ 1]

f(2) = 22 = 4 [since 2<3 and f(x) = x2 for 1<x≤ 3]

f(4) = 2(4) = 8 [since 4>3 and f(x) = 2x for x>3]

∴ f (– 1) + f (2) + f (4) = -3+4+8 = 9

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...