Question

The escape velocity for a body projected vertically upwards from the surface of Earth is 11 kms^-1 . If the body is projected at an angle of 45° with the vertical, the escape velocity will be …. kms^-1

(a)  \(\frac{11}{\sqrt{2}}\)

(b) 11√2

(c) 22

(d) 11

Answer 1

(d) 11

Escape velocity does not depends upon the angle of projection.