False
Let R be the relation defined on Z by mRn if m is a integral multiple of n.
Let mRm ∈ R
⇒ m is a integral multiple of m.
Which is true since m is integral multiple of itself.
Thus, R is reflexive.
Let mRn ∈ R
⇒ m is a integral multiple of n
⇒ m= zn ∀ z ∈ Z
⇒ n is not integral multiple of m.
⇒ nRm ∉ R
Thus, R is not symmetric.
Let mRn ∈ R and nRp ∈ R
⇒ m is a integral multiple of n and n is a integral multiple of p
⇒ m is a integral multiple of p
⇒ mRp ∈ R
Thus, R is transitive.
Hence, the given statement is false.