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+1 vote
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in Trigonometry by (49.2k points)
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Prove that cos 20° cos 40° cos 80° = 1/8

2 Answers

+1 vote
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Best answer

LHS = \(\cos20° \cos40°\cos 80°\)

\(= \frac 12[2\cos20° \cos40°]\cos80°\)

\(= \frac 12[\cos(20° + 40°) + \cos(20° - 40°)] \cos 80°\)

\(= \frac 12 [\cos60° + \cos(-20°)] \cos80° \)

\(= \frac 12\cos 80° [\frac 12 + \cos20°]\)

\(= \frac 14 \cos 80° + \frac 12 \cos 80° \cos 20°\)

\(= \frac 14 \cos 80° + \frac 14[ 2\cos 80° \cos 20°]\)

\(= \frac 14 \cos 80° + \frac 14[ \cos (80°+20°) + \cos (80°-20°]\)

\(= \frac 14\cos 80° + \frac 14[\cos100° + \cos60°]\)

\(= \frac 14\cos 80° + \frac 14[\cos(180°-80°) + \frac 12]\)

\(= \frac 14\cos 80° - \frac 14\cos80° + \frac 18\)    \(\{\because \cos(180° - 80°) = - \cos80°\}\)

\(= \frac 18 \)

= RHS

+4 votes
by (47.0k points)

LHS 

= (1/4) x cos 60° = 1/8 = RHS

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