1. (A) is identified from the molecular formula as methanol (CH3OH).
2. CH3OH – methanol on mild oxidation will give formaldehyde as (B). Aldehydes reduce Tollen’s reagent to silver mirror. So, (B) is HCHO (methanal)
3. Formaldehyde reacts with CH3 MgBr, followed by acid hydrolysis produces primary alcohol and (C) is identified from the formula as CH3 – CH2OH – Ethanol. Ethanol liberates H2 gas with metallic sodium.