1. An organic compound gives blue colour in Victor Meyer’s test means it must be a secondary alcohol. From the formula, it is identified as
Propan – 2- ol (A)
2. Propan – 2 – ol on reaction with Cu at 573 K gives Propanone as (B).
3. Propanone on treatment with CH3MgBr followed by acid hydrolysis will yield Tertiary butyl alcohol (CH3)3 C – OH as (C).
4. Tertiary butyl alcohol on reaction with copper at 573 K undergoes dehydration reaction to