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If the sides of a ∆ABC are a = 4, b = 6 and c = 8, then show that 4 cos B + 3 cos C = 2.

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If the sides of a ∆ABC are a = 4, b = 6 and c = 8, then show that 4 cos B + 3 cos C = 2.

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a = 4, b = 6, c = 8

To prove 4 cos B + 3 cos C = 2

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