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 Let A = \(\begin{bmatrix} 1 & 2 \\[0.3em] -1 & 3 \end{bmatrix}\), B = \(\begin{bmatrix} 4 & 0 \\[0.3em] 1 & 5 \end{bmatrix}\), C = \(\begin{bmatrix} 2 & 0 \\[0.3em] 1 & -2 \end{bmatrix}\) and a = 4, b = -2. Show that: (a + b)B = aB + bB

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Best answer

To prove: (a + b)B = aB + bB

Given, a = 4 and b = -2

Hence,

(a + b)B = aB + bB …proved

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