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If \(\begin{bmatrix} cosθ & sinθ \\[0.3em] -sinθ & cos θ \end{bmatrix}\), then show that A2 = \(\begin{bmatrix} cos2θ & sin2θ \\[0.3em] -sin2θ & cos2θ \end{bmatrix}\).

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As we know that:

2 sin θ cos θ = sin 2θ and cos2 θ – sin2 θ = cos 2θ

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