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in Matrices by (49.0k points)
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Find inverse, by elementary row operations (if possible), of the matrices.

\(\begin{bmatrix} 1 & 3 \\[0.3em] -5 & 7 \end{bmatrix}\)

1 Answer

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by (50.4k points)
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Best answer

To apply elementary row transformations we write:

A = IA where I is the identity matrix

We proceed with operations in such a way that LHS becomes I and the transformations in I give us a new matrix such that

I = XA

And this X is called inverse of A = A-1

So we have:

As we got Identity matrix in LHS.

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