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In a triangle ABC, A = 35° 17′ ; C = 45° 13′ ; b = 42.1 Solve the triangle

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The unknown parts are B, a, c, 

B = 180 – (A + C) = 180 – (35° 17′ + 45° 13′) = 99° 30′

To find sides, use sine formula

log c = log 42.1 + log sin 45° 31 – log sin 99° 30′

= 1.6243 + 1.8511 – 1.9940 

= 1.4754 – 1.9940 

= 1.4754 – [-1 + 0.9940] = 1.4814 

⇒ c = 30.3° 

Thus B = 99° 30′ ; a = 24.65° ; c = 30.3°

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