Let n be the initial number of moles and ri be the final number of moles. since pressure and volume remain the same, we have

PV = nRT = nR x 300 = n'R x 325

\(\frac{n'}{n}\) = \(\frac{300}{325}\) = \(\frac{12}{13}\)

Mass to be released = 13 - 12 = 1g