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A carnot engine operating between temperature T1 and T2 has efficiency \(\frac{1}{6}\) . When T2 is lowered by 62 K, its efficiency increases to . Then find the values of T1 and T2.

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Efficiency η = \(1 - \frac{T_2}{T_1}\)

in the first case :

 \(1 - \frac{T_2}{T_1}\) = \(\frac{1}{6}\) ⇒ \(\frac{T_2}{T_1}\) = \(\frac{5}{6}\)

In the second case : 

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