# A carnot engine operating between temperature T1 and T2 has efficiency 1/6 . When T2 is lowered by 62 K

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A carnot engine operating between temperature T1 and T2 has efficiency $\frac{1}{6}$ . When T2 is lowered by 62 K, its efficiency increases to . Then find the values of T1 and T2.

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Efficiency η = $1 - \frac{T_2}{T_1}$

in the first case :

$1 - \frac{T_2}{T_1}$ = $\frac{1}{6}$ ⇒ $\frac{T_2}{T_1}$ = $\frac{5}{6}$

In the second case :

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