A carnot engine operating between temperature T1 and T2 has efficiency 1/6 . When T2 is lowered by 62 K

Question

A carnot engine operating between temperature T₁ and T₂ has efficiency \(\frac{1}{6}\) . When T₂ is lowered by 62 K, its efficiency increases to . Then find the values of T₁ and T₂.

Answer 1

Efficiency η = \(1 - \frac{T_2}{T_1}\)

in the first case :

 \(1 - \frac{T_2}{T_1}\) = \(\frac{1}{6}\) ⇒ \(\frac{T_2}{T_1}\) = \(\frac{5}{6}\)

In the second case :