LIVE Course for free

Rated by 1 million+ students
Get app now
0 votes
in Heat and Thermodynamics by (51.0k points)
retagged by

A carnot engine operating between temperature T1 and T2 has efficiency \(\frac{1}{6}\) . When T2 is lowered by 62 K, its efficiency increases to . Then find the values of T1 and T2.

1 Answer

+1 vote
by (52.7k points)
selected by
Best answer

Efficiency η = \(1 - \frac{T_2}{T_1}\)

in the first case :

 \(1 - \frac{T_2}{T_1}\) = \(\frac{1}{6}\) ⇒ \(\frac{T_2}{T_1}\) = \(\frac{5}{6}\)

In the second case : 

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.