(a) 200 atoms of (x + 200) atoms of (y + 50) molecules of z2
According to the reaction,
1 atom of x reacts with one atom of y and one molecule of z to give product. In the case (a) 200 atoms of x, 200 atoms of y react with 50 molecules of z2 (4 part)
i.e. 50 molecules of z2 react with 50 atoms of x and 50 atoms of y.
Hence z is the limiting reagent.
(b) 1 mol of (x + 1) mol of (y + 3) mol of z2
According to the equation,
1 mole of z2 only react with one mole of x and one mole of y. If 3 moles of z2 are there, z2 is limiting reagent.
(c) 50 atoms of (x + 25) atoms of (y + 50) molecules of z2
25 atoms of y react with 25 atoms of x and 25 molecules of z2 . So y is the limiting reagent.
(d) 2.5 mol of (x + 5) mol of (y + 5) mol of z2
2.5 mol of x react with 2.5 mole of y and 2.5 mole of z2 . So x is the limiting reagent.