Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
846 views
in Derivatives by (50.4k points)
closed by

The maximum value of (1/x)x is:

A. e
B. ee
C. c1/e
D. (1/e)1/e

1 Answer

+2 votes
by (49.0k points)
selected by
 
Best answer

Now applying the product rule of differentiation we get

Now we will find the critical point by equating equation (i) to 0, we get

Hence f(x) has a stationary point at x = 1/e.

i.e the maximum value of f(1/e) = e1/e

So the correct option is option C.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...