Question

If g(x) = e^2x+e^x-1 and h(x) = 3x^2-1 the value of g(h(0)) is

Answer 1

Given that g(x) =e^2x+e^x-1

H(x) =3x^2-1

Now

g(h(0))=g(3x^2-1)

=g(3(0)-1)

=g(-1)

=e^2(-1)+e^(-1) - 1

=1/e^2+1le - 1

After lcm

=1+e-1 /e^2

=e/e^2

=1/e