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in Calculus by (49.0k points)
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Find the area of the region bounded by the parabola y2 = 2px, x2 = 2py.

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Given parabolas are y2 = 2px …. (i) and x2 = 2py …. (ii)

Now, from equation (ii) we have

y = x2/2p

Putting the value of y in equation (i), we have

(x2/2p)2 = 2px

x4/4p2 = 2px

x4 = 8p3x

x4 – 8p3x = 0

x(x3 – 8p3) = 0

So, x = 0 or x3 – 8p3 = 0 ⇒ x = 2p

Now, the required area is

Therefore, the required area is 4/3 p2 sq. units.

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