Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
2.2k views
in Differential Equations by (50.4k points)
closed by

Solve the differential equation (1+ y2) tan-1x dx + 2y (1 + x2) dy = 0

1 Answer

+1 vote
by (49.0k points)
selected by
 
Best answer

Given: (1+y2) tan-1x dx + 2y(1+x2) dy=0

To find: solution of given differential equation

Re-writing the equation as

For LHS

Assume tan-1 = t

For RHS

Assume 1+y2=z

2y dy=dz

Now substituting and integrating both sides

Is the solution for the given differential equation.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...