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A sample of hydrated copper sulphate is heated to drive off the water of crystallization, cooled and reweighed 0.869 g of CuSO4 aH2O gave a residue of 0.556 g. Find the molecular formula of hydrated copper sulphate.

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0.869 g of CuSO4 .aH2O gave a residue of 0.556 g of Anhydrous CuSO4 .

∴ Weight of a H2O molecule = 0.869 – 0.556 

= 0.313 g 

Molecular weight of H2O = (1 x 2) + 16 

= 2 + 16 

= 18

No. of moles of water = Mass / (Molecular mass) 

CuSO4.5H2O – Molecular mass = 63.5 + 32 + 64 + 90 = 249.5 g 

249.5 g of CuSO4.5H2O on heating gives 159.5 g of CuSO4

0.869 g of CuSO4.aH2O on heating gives = 159.5/249.5 x 0.869 = 0.556 g of anhydrous CuSO. ∴ a = 5 

The molecular formula of hydrated copper sulphate = CuSO4.5H2O

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