Question

Calculate the mass of the following atoms in amu, 

(a) Helium (mass of He = 6.641 x 10^-24 g) 

(b) Silver (mass of Ag = 1.790 x 10^-22 g) 

1 amu = 1.66056 x 10^-24

Answer 1

(a) The mass of Helium atom in amu = \(\frac{6.641\times10^{-24}}{1.66056\times10^{-24}}\) = 3.9992 amu.

(b) The mass of Silver atom in amu = \(\frac{1.790\times10^{-22}}{1.66056\times10^{-24}}\) = 107.79 amu.