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The density of water at room temperature is 1.0 g/ml. How many molecules are there in a drop of water if its volume is 0.05 ml?

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Volume of drop of water = 0.05 ml 

Mass of a drop of water = Volume x Density 

= 0.05 ml x 1.0 g / ml. 

= 0.05 g 

Molar mass of water (H2O) = 18 g 

18 g of water = 1 mole

0.05 g of water = 1/8 x 0.05 = 0.0028 mol. 

No. of molecules present in one mole of water = 6.023 x 1023 

No. of molecules present in 0.0028 mole of water = \(\frac{6.023\times10^{23}\times0.0028}{1}\) 

= 1.68 x 1021 water molecules

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