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Explain structures of diborane and boric acid. 

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(a) Diborane 

B2H6 is an electron-deficient compound. B2H6 has only 12 electrons – 6 efrom 6 H atoms and 3 eeach from 2 B atoms. Thus, after combining with 3 H atoms, none of the boron atoms has any electrons left. X-ray diffraction studies have shown the structure of diborane 

as:

2 boron and 4 terminal hydrogen atoms (Ht) lie in one plane, while the other two bridging hydrogen atoms (Hb) lie in a plane perpendicular to the plane of boron atoms. Again, of the two bridging hydrogen atoms, one H atom lies above the plane and the other lies below the plane. The terminal bonds are regular two-centre two-electron (2c 2e ) bonds, while the two bridging (B–H–B) bonds are three-centre two-electron (3c 2e– ) bonds. 

(b) Boric acid 

Boric acid has a layered structure. Each planar BO3 unit is linked to one another through H atoms. The H atoms form a covalent bond with a BO3 unit, while a hydrogen bond is formed with another BO3 unit. In the given figure, the dotted lines represent hydrogen bonds. 

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