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Balance the following equation by ion-electron method In acidic medium.

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Balance the following equation by ion-electron method In acidic medium.

(1) S2O32- + I2 → S2O42- + SO2 + I-

(2) Sb3+ + MnO4 → Sb5+ + Mn2+

(3) MnO4- + I- → MnO2 + I2

(4) MnO4- + Fe2+ → Mn2+ + Fe3+

(5) Cr(OH)4- + H2O2 → CrO4-

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(1) S2O32- + I2 → S2O42- + SO2 + I-

Oxidation half reaction:

Reduction half reaction:

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