Question

The molecules of a given mass of a gas have rms velocity of 200 ms 1 at 27°C and 1.0 × 10s Nm^-2 pressure. When the temperature and pressure of the gas are respectively. 127 °C and 0.05 × 10s Nm^-2 . 

Find the rms velocity of its molecules in ms^-1

Answer 1

  T₁ = 27° C + 273 = 300 K, T₂ = 127° C + 273 = 400 K

rms speed of molecules is v_rms = \(\sqrt{\frac{3RT}{M}}\)

So it depends only on temperature,