Question

A n atom of an element contains 35 electrons and 45 neutrons. Deduce 

i. The number of protons 

ii. The electronic configuration for the element 

iii. All the four quantum numbers for the last electron

Answer 1

An element X contains 35 electrons, 45 neutrons 

i. The number of protons must be equal to the number of electrons. So the number of protons = 35. 

ii. Number of electrons = 35. So the electronic configuration is 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁵ . 

iii. The last electron i.e. 5^th electron in 4p orbital has the following quantum numbers. n = 4, l = 1, m = +1, s = +1/2