Question

Find the equation of a plane which is at a distance 3√3 units from origin and the normal to which is equally inclined to coordinate axis.

Answer 1

As the normal to the plane is equally inclined to the axes we have,

cos α = cos β = cos γ

So, cos² α + cos² α + cos² α = 1

3 cos² α = 1 ⇒ cos α = ± 1/√3

And, cos α = cos β = cos γ = ± 1/√3

Thus, the equation of the plane is x + y + z = 9