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+1 vote
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in 3D Coordinate Geometry by (55.5k points)
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The area of the quadrilateral ABCD, where A(0,4,1), B (2, 3, –1), C(4, 5, 0)and D (2, 6, 2), is equal to

A. 9 sq. units
B. 18 sq. units
C. 27 sq. units
D. 81 sq. Units

1 Answer

+2 votes
by (50.4k points)
selected by
 
Best answer

Given,

A(0,4,1), B (2, 3, –1), C(4, 5, 0) and D (2, 6, 2), therefore

Since, opposite vectors of this parallelogram are equal and opposite, therefore ABCD is a parallelogram and we know area of a parallelogram ABCD is

|AB × CD|

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