Question

A mass M is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes SHM of time period T. If the mass is increased by m, the time period becomes 5T/3. What is the ratio m/M?

Answer 1

With mass M, the time period of the spring is T = 2π\(\sqrt{\frac{M}{K}}\)

With mass M + m, the time period becomes